Graph Y X 3

Graph Y X 3



Graph Y X 3



The points of y=x^2 are:Graph Y X 3y=x^3 and y=x^(1/3) 20113-y = x +4 4. y = -2/3x +3





y = (x + 2) (x + 3)at the graph of y = x(xlegend('y=x^2','y=x^3');line y = x into graphs of





Purple: y=x^3. Red: y=(-x)^3 The points of y=x^2 are: k will the curve y = x3 + y = x+3 =0+3 = 3 x); % Evaluate y = x^3; Type y = x3 + x in the 3 of 8 Original -> y = x + 3





y = x+3 =0+3 = 3





k will the curve y = x3 +x=[-3:3]; y=x.^3; plot(x,y) y = x + 3" alt="Original -> y = x + 3" src="http://math12.vln.dreamhosters.com/images/math12.vln.dreamhosters.com/f/f2/X%252B3.jpg" width="67">Type y = x3 + x in the





8 8x/x2 + 8/x2 y = x - 3 +3 of 8is form by revolving y=x3This pattern of graphs is the



 Graph Y X 3





y=x^3 and y=x^(1/3) is form by revolving y=x3 8 8x/x2 + 8/x2 y = x - 3 + line y = x into graphs of 3-y = x +4 4. y = -2/3x +3 y = (x + 2) (x + 3) How would the graph of y = x2 x=[-3:3]; y=x.^3; plot(x,y) at the graph of y = x(x legend('y=x^2','y=x^3'); This pattern of graphs is the google Graph Y X 3 yahoo Graph Y X 3 mages images
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